Answer :
To prepare 300.0 mL of a 0.500 M NaOH solution, you will need to add 25.0 mL of the 6.00 M NaOH solution.
To prepare a solution with a concentration of 0.500 M, you will need to calculate the volume of the 6.00 M NaOH solution needed. The formula to use is:
M1V1 = M2V2
Where:
M1 is the initial concentration of the NaOH solution (6.00 M)
V1 is the initial volume of the NaOH solution (unknown)
M2 is the final concentration of the diluted solution (0.500 M)
V2 is the final volume of the diluted solution (300.0 mL)
Let's solve for V1:
(6.00 M)(V1) = (0.500 M)(300.0 mL)
To solve for V1, we can rearrange the equation:
V1 = (0.500 M)(300.0 mL) / (6.00 M)
V1 = (0.500 M)(300.0 mL) / (6.00 M)
V1 = 25.0 mL
Therefore, to prepare 300.0 mL of a 0.500 M NaOH solution, you will need to add 25.0 mL of the 6.00 M NaOH solution.
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