Answer :
Final answer:
The duration of the current in seconds is approximately 1900 seconds.
Explanation:
To calculate the duration of the current in seconds, we can use Faraday's laws of electrolysis. According to Faraday's first law, the mass of a substance deposited is directly proportional to the amount of charge passed through the electrolyte.
The equation to calculate the amount of substance deposited is:
Mass (g) = (Current (A) × Time (s) × Molar mass (g/mol)) / (Faraday's constant (C/mol))
In this case, we have the mass of chromium metal (1.0 g), the current (3.0 A), and the molar mass of chromium (52.00 g/mol). We need to calculate the time (duration of the current) in seconds.
Let's plug in the values into the equation:
1.0 g = (3.0 A × Time (s) × 52.00 g/mol) / (Faraday's constant)
Now, we can rearrange the equation to solve for Time (s):
Time (s) = (1.0 g × Faraday's constant) / (3.0 A × 52.00 g/mol)
Faraday's constant is approximately 96,485 C/mol.
Let's substitute the values and calculate:
Time (s) = (1.0 g × 96,485 C/mol) / (3.0 A × 52.00 g/mol)
Time (s) ≈ 1900 seconds
Learn more about calculating the duration of current in electrolysis here:
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