High School

What is the phase angle in an RLC circuit with [tex]R = 9.9 \, k\Omega[/tex], [tex]C = 1.5 \, \mu F[/tex], and [tex]L = 250 \, mH[/tex]?

The generator supplies an RMS voltage of 115 V at a frequency of 60.0 Hz.

Answer :

Final answer:

The phase angle in the given RLC circuit is approximately 0 degrees.

Explanation:

In an RLC circuit, the phase angle represents the phase difference between the current and voltage. It can be found using the formula cosφ = R/⇃ where φ is the phase angle and R is the resistance. In this case, the resistance is 9.9 kΩ, which is equivalent to 9900 Ω.

The generator supplies an RMS voltage of 115 V, so the voltage across the circuit is 115 V. The frequency is 60.0 Hz, and we can convert this to angular frequency (w) using the formula w = 2πf. Substituting the values, we get w ≈ 2π×60.0 ≈ 376.99 rad/s.

Now we can calculate the phase angle using the formula cosφ = R/⇃. Substituting R = 9900 Ω and ⇃ = 1/(wC) = 1/(376.99×1.5×10-6), we get cosφ ≈ 9900/(376.99×1.5×10-6) ≈ 5.514.

Since the cosine of the phase angle cannot exceed 1, we can conclude that the phase angle is approximately 0 degrees.

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