Answer :
The first step for solving this expression is to know that the root of a product is equal to the product of the roots of each factor. Knowing this,, the expression becomes the following:
[tex] \sqrt[3]{27} \sqrt[3]{ x^{9} } [/tex]
Write the number in the first square root in exponential form with a base of 3.
[tex] \sqrt[3]{ 3^{3} } \sqrt[3]{ x^{9} } [/tex]
Now reduce the index of the radical and exponent in the second square root with 3.
[tex] \sqrt[3]{ 3^{3} } [/tex] x³
Lastly,, reduce the index of the radical and exponent with 3 to get your final answer.
3x³
This means that the correct answer to your question will be option B.
Let me know if you have any further questions.
:)
[tex] \sqrt[3]{27} \sqrt[3]{ x^{9} } [/tex]
Write the number in the first square root in exponential form with a base of 3.
[tex] \sqrt[3]{ 3^{3} } \sqrt[3]{ x^{9} } [/tex]
Now reduce the index of the radical and exponent in the second square root with 3.
[tex] \sqrt[3]{ 3^{3} } [/tex] x³
Lastly,, reduce the index of the radical and exponent with 3 to get your final answer.
3x³
This means that the correct answer to your question will be option B.
Let me know if you have any further questions.
:)
The value of the expression ∛27x⁹ is 9x³.
The given expression is ∛27x⁹.
Cube root of twenty seven times of x power nine.
We can split the terms inside the cube root.
27=3×3×3
∛x⁹ = x³
Now let us plug in the above expression.
= 3√3³ × x⁹
= 3√3³ × √ x⁹
= 3 × 3 × x³
= 9x³.
Hence, the value of the expression ∛27x⁹ is 9x³.
To learn more on Expressions click:
https://brainly.com/question/14083225
#SPJ6
