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------------------------------------------------ The volume of a gas is 200.0 mL with a pressure of 2.00 atm. When the volume of the gas is reduced to 10 mL, what is the new pressure if the temperature remains the same?

Answer :

Answer:

40 atm.

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 200 mL

Initial pressure (P₁) = 2 atm

Final volume (V₂) = 10 mL

Temperature = constant

Final pressure (P₂) =?

The final pressure of the gas can be obtained by using the Boyle's law equation as shown below:

P₁V₁ = P₂V₂

2 × 200 = P₂ × 10

400 = P₂ × 10

Divide both side by 10

P₂ = 400 / 10

P₂ = 40 atm

Thus, the final pressure of the gas is 40 atm.

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