The half-life of Uranium-235 is 704 million years, and the radioactive decay of 1 kg of U-235 releases [tex]6.7 \times 10^{13}[/tex] J. If the overall efficiency of converting the energy of U-235 into fluorescent light is 11%, how much energy from 1 kg of U-235 would be converted to fluorescent light?

A) [tex]7.37 \times 10^{13}[/tex] J
B) [tex]6.7 \times 10^{13}[/tex] J
C) [tex]7.37 \times 10^{12}[/tex] J

The energy release from the radioactive decay of 1 kilogram of Uranium-235 is given as 6.7X 10¹³ J. If the efficiency of converting this energy into fluorescent light is 11%, the energy actually converted can be found by taking 11% of 6.7X 10¹³ J. We do this by multiplying 6.7X 10¹³ J by 0.11, which gives us approximately 7.37 X 10¹² J. Therefore, the energy from 1 kilogram of Uranium-235 that would theoretically be converted into fluorescent light is 7.37 X 10¹² J so the correct answer is (c). The overall efficiency of converting the energy of U-235 into fluorescent light is given as 11%. This means only 11% of the total energy released in the radioactive decay is converted into fluorescent light. To find the energy converted to fluorescent light, you can multiply the total energy released by the efficiency factor.

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