Answer :
The magnitude of the speed at which the person slides backward is 0.899 m/s. When the person throws the object at an angle above the horizontal, they start sliding backward due to the conservation of momentum.
To calculate the magnitude of the speed at which the person slides backward, we need to consider the conservation of momentum. The initial momentum of the system is equal to the final momentum. Initially, the person and the object are at rest, so the total momentum is zero. After the person throws the object, they start sliding backward, gaining momentum in the opposite direction.
We can calculate the magnitude of the person's sliding speed by using the equation:
m1v1 + m2v2 = (m1 + m2)vf
where
m1 = mass of the person
= 124 kg
v1 = initial velocity of the person
= 0 m/s (at rest)
m2 = mass of the object
= 4.20 kg
v2 = initial velocity of the object
= 20.1 m/s
vf = final velocity of the system (person and object)
= -v (negative since it represents the opposite direction)
Plugging in the values:
(124 kg)(0 m/s) + (4.20 kg)(20.1 m/s) = (124 kg + 4.20 kg)(-v)
0 + 84.42 = 128.2(-v)
Solving for v:
v = -0.658 m/s
The magnitude of the sliding speed is the absolute value of v:
|v| = 0.658 m/s
Therefore, the magnitude of the speed at which the person slides backward is 0.658 m/s.
When the person throws the object at an angle above the horizontal, they start sliding backward due to the conservation of momentum. The magnitude of the person's sliding speed is determined by the initial speed of the object and the masses of the person and the object. In this case, the magnitude of the sliding speed is calculated to be 0.658 m/s.
To know more about speed ,visit:
https://brainly.com/question/13943409
#SPJ11
