Answer :
1. The volume of the ball is approximately 0.1 cubic meters.
2. No, a 50 lb child would not be able to hold the ball under the water.
3. When a dirigible or a blimp remains in one position in the air, it is because its total weight is equal to that of the air it displaces.
1. To calculate the volume of the ball immersed in water:
The upward force exerted by the ball when immersed in water is equal to the weight of the water displaced by the ball. This is given as 980 N.
Density of water = 1000 kg/m^3
Acceleration due to gravity = 9.8 m/s^2
Using the formula for weight, which is given by weight = density * volume * acceleration due to gravity, we can rearrange the formula to find the volume:
Volume = Weight / (Density * Acceleration due to gravity)
Volume = 980 N / (1000 kg/m^3 * 9.8 m/s^2)
Volume ≈ 0.1 m^3
Therefore, the volume of the ball is approximately 0.1 cubic meters.
2. Would a 50 lb child be able to hold the ball under the water?
To determine if the 50 lb child can hold the ball under the water, we need to compare the weight of the ball with the force exerted by the child.
Weight of the ball = 980 N
Weight of the child = 50 lb
Convert the weight of the child to Newtons:
Weight of the child = 50 lb * 4.448 N/lb
Weight of the child ≈ 222.4 N
Since the weight of the child (222.4 N) is less than the weight of the ball (980 N), the child would not be able to hold the ball under the water.
3. When a dirigible or a blimp remains in one position in the air, it is because...
The blimp remains in one position in the air because its total weight is equal to the weight of the air it displaces. This is known as buoyancy.
Therefore, the correct answer is:
Its total weight is equal to that of the air it displaces.
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