The average blue whale weighs 300,000 pounds (136,000 kilograms). The average man is [tex]\frac{1}{1,818}[/tex] the weight of a blue whale. How much does the average man weigh in pounds?

Select one of the following:

A. [tex]242 \frac{7}{425}[/tex] lbs
B. [tex]165 \frac{5}{303}[/tex] lbs
C. [tex]205 \frac{3}{890}[/tex] lbs
D. [tex]234 \frac{7}{303}[/tex] lbs

We are given that the average blue whale weighs

[tex]$$300,\!000 \text{ pounds},$$[/tex]

and the average man weighs

[tex]$$\frac{1}{1818}$$[/tex]

of the weight of a blue whale. Therefore, the average man's weight in pounds is

[tex]$$\text{Weight} = \frac{300,\!000}{1818}.$$[/tex]

### Step 1. Simplify the Fraction
Notice that both the numerator and the denominator are divisible by 6. Dividing both by 6 we get

[tex]$$300,\!000 \div 6 = 50,\!000 \quad \text{and} \quad 1818 \div 6 = 303.$$[/tex]

Thus, the weight becomes

[tex]$$\frac{300,\!000}{1818} = \frac{50,\!000}{303}.$$[/tex]

### Step 2. Express as a Mixed Number
To write [tex]$\frac{50,\!000}{303}$[/tex] as a mixed number, first determine the integer part by performing the division:

Divide 50,000 by 303. We compute

[tex]$$303 \times 165 = 303 \times (160 + 5) = 303 \times 160 + 303 \times 5.$$[/tex]

First, calculate

[tex]$$303 \times 160 = 48,\!480,$$[/tex]

then

[tex]$$303 \times 5 = 1,\!515.$$[/tex]

So,

[tex]$$303 \times 165 = 48,\!480 + 1,\!515 = 49,\!995.$$[/tex]

Since

[tex]$$50,\!000 - 49,\!995 = 5,$$[/tex]

the remainder is 5. Therefore, we can express the weight as

[tex]$$\frac{50,\!000}{303} = 165 + \frac{5}{303}.$$[/tex]

Thus, the average man weighs

[tex]$$165 \frac{5}{303} \text{ pounds}.$$[/tex]

### Final Answer
The correct answer is

[tex]$$165 \frac{5}{303} \text{ lbs}.$$[/tex]