Answer :
Given that the calories burned while jogging are modeled by the formula
[tex]$$
\text{Calories burned} = \text{Factor} \times \text{Weight} \times \text{Distance},
$$[/tex]
we can substitute the known values. Here, the jogger burns 106 calories while jogging 1 mile, and the factor for jogging is given as [tex]$0.65$[/tex]. Thus, we have
[tex]$$
106 = 0.65 \times \text{Weight} \times 1.
$$[/tex]
To solve for the weight, rearrange the equation:
[tex]$$
\text{Weight} = \frac{106}{0.65}.
$$[/tex]
Calculating this gives
[tex]$$
\text{Weight} \approx 163.08.
$$[/tex]
Rounding to the nearest pound, the person's weight is approximately [tex]$163$[/tex] pounds.
[tex]$$
\text{Calories burned} = \text{Factor} \times \text{Weight} \times \text{Distance},
$$[/tex]
we can substitute the known values. Here, the jogger burns 106 calories while jogging 1 mile, and the factor for jogging is given as [tex]$0.65$[/tex]. Thus, we have
[tex]$$
106 = 0.65 \times \text{Weight} \times 1.
$$[/tex]
To solve for the weight, rearrange the equation:
[tex]$$
\text{Weight} = \frac{106}{0.65}.
$$[/tex]
Calculating this gives
[tex]$$
\text{Weight} \approx 163.08.
$$[/tex]
Rounding to the nearest pound, the person's weight is approximately [tex]$163$[/tex] pounds.
