College

Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a [tex]\checkmark[/tex] chance that the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

2. If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is [tex]\square[/tex].

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Answer :

Let's solve this question step by step.

### First Scenario

We have a heterozygous male with the genotype Ww mating with a homozygous recessive female with the genotype ww.

To determine the probability of the offspring being heterozygous (Ww), we can use a Punnett square:

1. Set up the Punnett square:

- Male gametes (Ww): W and w
- Female gametes (ww): w and w

```
Female
w w
-------------------
W | Ww | Ww |
w | ww | ww |
```

2. Fill the Punnett square:

- Top left box: Ww (from W and w)
- Top right box: Ww (from W and w)
- Bottom left box: ww (from w and w)
- Bottom right box: ww (from w and w)

3. Probability Calculation:

- There are two Ww combinations out of four total potential combinations.
- Thus, the probability that an offspring will be heterozygous (Ww) is 2 out of 4, which simplifies to 0.5 (or 50%).

### Second Scenario

Now, let's consider a heterozygous individual (Ww) crossed with a homozygous dominant individual (WW). We need to find the probability of having a homozygous recessive (ww) offspring.

1. Set up the Punnett square:

- Heterozygous individual (Ww): W and w
- Homozygous dominant individual (WW): W and W

```
Female
W W
-------------------
W | WW | WW |
w | Ww | Ww |
```

2. Fill the Punnett square:

- Top left box: WW (from W and W)
- Top right box: WW (from W and W)
- Bottom left box: Ww (from w and W)
- Bottom right box: Ww (from w and W)

3. Probability Calculation:

- In this setup, there are no boxes showing the genotype ww.
- Therefore, the probability of having a homozygous recessive (ww) offspring is 0 out of 4, which is 0%.

### Conclusion

- The chance of the offspring being heterozygous (Ww) in the first scenario is 0.5 (or 50%).
- The probability of having a homozygous recessive (ww) offspring in the second scenario is 0%.