Of the people who fished at Clearwater Park today, 34 had a fishing license, and 24 did not. Of the people who fished at Mountain View Park today, 42 had a license, and 28 did not. (No one fished at both parks.)

Suppose that one fisher from each park is chosen at random. What is the probability that the fisher chosen from Clearwater had a license and the fisher chosen from Mountain View did not have a license?

a) \(\frac{17}{50}\)

b) \(\frac{34}{50}\)

c) \(\frac{24}{50}\)

d) \(\frac{14}{50}\)

The probability that the fisher chosen from Clearwater had a license and the fisher chosen from Mountain View did not have a license is 17/145 or approximately 0.1172.

Explanation:

To find the probability that the fisher chosen from Clearwater had a license and the fisher chosen from Mountain View did not have a license, we need to find the product of the probabilities for each event. The probability of choosing a fisher with a license from Clearwater is 34/58 (since there are 34 fishers with a license out of a total of 58 fishers at Clearwater). The probability of choosing a fisher without a license from Mountain View is 28/70 (since there are 28 fishers without a license out of a total of 70 fishers at Mountain View). Therefore, the probability is (34/58) * (28/70) = 17/145 or approximately 0.1172.