Which equation, when solved, results in a different value of [tex]x[/tex] than the other three?

A. [tex]8.3 = -0.6x + 11.3[/tex]

B. [tex]11.3 = 8.3 + 0.6x[/tex]

C. [tex]11.3 - 0.6x = 8.3[/tex]

D. [tex]8.3 - 0.6x = 11.3[/tex]

Answer :

To determine which equation results in a different value of [tex]\( x \)[/tex] than the others, let's solve each one step by step:

1. Equation 1: [tex]\( 8.3 = -0.6x + 11.3 \)[/tex]

- Subtract 11.3 from both sides:

[tex]\( 8.3 - 11.3 = -0.6x \)[/tex]

- Simplify:

[tex]\( -3 = -0.6x \)[/tex]

- Divide both sides by -0.6:

[tex]\( x = \frac{-3}{-0.6} \)[/tex]

- Solve for [tex]\( x \)[/tex]:

[tex]\( x = 5 \)[/tex]

2. Equation 2: [tex]\( 11.3 = 8.3 + 0.6x \)[/tex]

- Subtract 8.3 from both sides:

[tex]\( 11.3 - 8.3 = 0.6x \)[/tex]

- Simplify:

[tex]\( 3 = 0.6x \)[/tex]

- Divide both sides by 0.6:

[tex]\( x = \frac{3}{0.6} \)[/tex]

- Solve for [tex]\( x \)[/tex]:

[tex]\( x = 5 \)[/tex]

3. Equation 3: [tex]\( 11.3 - 0.6x = 8.3 \)[/tex]

- Subtract 8.3 from both sides:

[tex]\( 11.3 - 8.3 = 0.6x \)[/tex]

- Simplify:

[tex]\( 3 = 0.6x \)[/tex]

- Divide both sides by 0.6:

[tex]\( x = \frac{3}{0.6} \)[/tex]

- Solve for [tex]\( x \)[/tex]:

[tex]\( x = 5 \)[/tex]

4. Equation 4: [tex]\( 8.3 - 0.6x = 11.3 \)[/tex]

- Subtract 8.3 from both sides:

[tex]\( -0.6x = 11.3 - 8.3 \)[/tex]

- Simplify:

[tex]\( -0.6x = 3 \)[/tex]

- Divide both sides by -0.6:

[tex]\( x = \frac{3}{-0.6} \)[/tex]

- Solve for [tex]\( x \)[/tex]:

[tex]\( x = -5 \)[/tex]

The equations that have the same solution for [tex]\( x = 5 \)[/tex] are the first three equations. The equation that results in a different value of [tex]\( x \)[/tex] is the fourth equation, which gives [tex]\( x = -5 \)[/tex]. Therefore, the fourth equation, [tex]\( 8.3 - 0.6x = 11.3 \)[/tex], is the one with a different solution.