High School

A portable CD player uses a current of 7.52 mA at a potential difference of 3.66 V. How much energy does the player use in 37.1 s?
A) Depends on the efficiency of the CD player
B) Not enough information provided
C) 1.00 J
D) 1.43 kJ

Answer :

The energy used by the CD player is 1.00 J.Option (c).

To find the energy used by the CD player, we can use the formula:

Energy = Power × Time

Given that:

Current (I) = 7.52 mA = 7.52 × [tex]10^{-3}[/tex] A

Potential difference (V) = 3.66 V

Time (t) = 37.1 s

First, we need to find the power (P) used by the CD player. Power is given by:

P = IV

Substitute the given values:

P = (7.52 × [tex]10^{-3}[/tex] A) × (3.66 V)

P = 0.0275 W

Now, we can calculate the energy:

Energy = (0.0275 W) × (37.1 s)

Energy = 1.02025 J

So, the energy used by the CD player is approximately 1.02 J.

Therefore, the correct answer is 1.00 J.Option (c).

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