Answer :

Answer:

Answer:

2.77 × 10²³ Br Atoms


Solution:

Data Given:

Mass of CH₂Br₂ = 39.9 g


M.Mass of CH₂Br₂ = 173.83 g.mol⁻¹


Step 1: Calculate Moles of CH₂Br₂ as,


Moles = Mass ÷ M.Mass


Putting values,


Moles = 39.9 g ÷ 173.83 g.mol⁻¹


Moles = 0.23 mol


Step 2: Calculate number of CH₂Br₂ Molecules,


As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of CH₂Br₂ Molecules can be written as,


Moles = Number of CH₂Br₂ Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹


Solving for Number of CH₂Br₂ Molecules,


Number of CH₂Br₂ Molecules = Moles × 6.022 × 10²³ Molecules.mol⁻¹


Putting value of moles,


Number of CH₂Br₂ Molecules = 0.23 mol × 6.022 × 10²³ Atoms.mol⁻¹


Number of CH₂Br₂ Molecules = 1.38 × 10²³ CH₂Br₂ Molecules


Step 3: Calculate Number of Br Atoms:


As,


1 Molecule of CH₂Br₂ contains = 2 Atoms of Br


So,


1.38 × 10²³ Molecules of CH₂Br₂ will contain = X Atoms of Br


Solving for X,


X = (1.38 × 10²³ CH₂Br₂ × 2 Br) ÷ 1 CH₂Br₂


X = 2.77 × 10²³ Br Atoms

Explanation: