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------------------------------------------------ A 19.8 kg block is dragged over a rough, horizontal surface by a constant force of 163 N acting at an angle of 29.6° above the horizontal. The block is displaced 27.1 m, and the coefficient of kinetic friction is 0.137.

Find the work done by the 163 N force. The acceleration of gravity is 9.8 m/s². Answer in units of J.

Answer :

Final answer:

The work done by the 163 N force on the 19.8 kg block is approximately 4022 J.

Explanation:

To find the work done by the 163 N force on the 19.8 kg block, we need to calculate the component of the force in the direction of displacement. This can be done by multiplying the force by the cosine of the angle between the force and the displacement:

Work = Force * Cos(angle) * displacement

Work = 163 N * Cos(29.6°) * 27.1 m

Work ≈ 4022 J

Therefore, the work done by the 163 N force is approximately 4022 J.

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