Answer :
To solve the given system of equations using elimination, follow these steps:
We have the system of equations:
1. [tex]\(5a + 5b = 25\)[/tex]
2. [tex]\(-5a + 5b = 35\)[/tex]
The goal of elimination is to remove one of the variables by adding or subtracting the equations. Here’s how you can do it:
1. Add the two equations together:
[tex]\[
(5a + 5b) + (-5a + 5b) = 25 + 35
\][/tex]
2. When you add the left-hand sides together, notice that the [tex]\(5a\)[/tex] and [tex]\(-5a\)[/tex] terms will cancel each other out:
[tex]\[
5b + 5b = 10b
\][/tex]
3. Now, add the right-hand sides:
[tex]\[
25 + 35 = 60
\][/tex]
4. The resulting equation after performing the addition is:
[tex]\[
10b = 60
\][/tex]
Thus, the resulting equation by using elimination is [tex]\(10b = 60\)[/tex].
We have the system of equations:
1. [tex]\(5a + 5b = 25\)[/tex]
2. [tex]\(-5a + 5b = 35\)[/tex]
The goal of elimination is to remove one of the variables by adding or subtracting the equations. Here’s how you can do it:
1. Add the two equations together:
[tex]\[
(5a + 5b) + (-5a + 5b) = 25 + 35
\][/tex]
2. When you add the left-hand sides together, notice that the [tex]\(5a\)[/tex] and [tex]\(-5a\)[/tex] terms will cancel each other out:
[tex]\[
5b + 5b = 10b
\][/tex]
3. Now, add the right-hand sides:
[tex]\[
25 + 35 = 60
\][/tex]
4. The resulting equation after performing the addition is:
[tex]\[
10b = 60
\][/tex]
Thus, the resulting equation by using elimination is [tex]\(10b = 60\)[/tex].
