College

Complete the synthetic division problem below:

[tex]-1 \longdiv {2 \ 7 \ 5}[/tex]

What is the quotient in polynomial form?

A. [tex]2x + 5[/tex]

B. [tex]x + 5[/tex]

C. [tex]x - 5[/tex]

D. [tex]2x - 5[/tex]

Answer :

To solve the problem of dividing the polynomial [tex]\(2x + 7\)[/tex] by [tex]\(x + 1\)[/tex] using synthetic division, let's go through the steps below:

1. Identify the Dividend and Divisor:
The polynomial we are dividing is [tex]\(2x + 7\)[/tex], and the divisor is [tex]\(x + 1\)[/tex]. In synthetic division, we use the root of the divisor, which is [tex]\(-1\)[/tex], for calculations.

2. Set up the Synthetic Division Table:
Write the coefficients of the polynomial [tex]\(2x + 7\)[/tex] in a row. Since the polynomial is linear, the coefficients are [2, 7]. Below this row, we place the root of the divisor, which is [tex]\(-1\)[/tex].

3. Carry Down the Leading Coefficient:
To begin, carry down the leading coefficient, which is [tex]\(2\)[/tex], to the bottom row.

4. Multiply and Add:
- Multiply the number just brought down ([tex]\(2\)[/tex]) by the root of the divisor ([tex]\(-1\)[/tex]). This gives [tex]\(-2\)[/tex].
- Add this result to the next coefficient (7): [tex]\(7 + (-2) = 5\)[/tex].

5. Complete the Process:
There are no more coefficients in the original polynomial, so we finish the process here. At the end, we will have the numbers in the bottom row: [2, 5].

6. Interpret the Result:
The numbers in the bottom row represent the coefficients of the quotient polynomial. So, we have the quotient as [tex]\(2x + 5\)[/tex].

Therefore, the quotient of the division in polynomial form is [tex]\(2x + 5\)[/tex].

Thus, the correct choice is:
A. [tex]\(2x + 5\)[/tex]