College

Karissa begins to solve the equation:

\[
\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4)
\]

Her work is correct and is shown below:

\[
\begin{array}{c}
\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4) \\
\frac{1}{2} x-7+11=\frac{1}{2} x-x+4 \\
\frac{1}{2} x+4=-\frac{1}{2} x+4
\end{array}
\]

When she subtracts 4 from both sides, \(\frac{1}{2} x=-\frac{1}{2} x\) results. What is the value of \(x\)?

A. \(-1\)
B. \(\frac{1}{2}\)
C. \(0\)
D. \(\frac{1}{2}\)

Answer :

- Add $\frac{1}{2}x$ to both sides of the equation $\frac{1}{2}x = -\frac{1}{2}x$.
- Simplify the equation to find $x = 0$.
- Verify the solution by substituting $x=0$ into the original equation.
- The value of $x$ is $\boxed{0}$.

### Explanation
1. Understanding the Equation
We are given the equation $\frac{1}{2}x = -\frac{1}{2}x$. Our goal is to find the value of $x$ that satisfies this equation.

2. Solving for x
To solve for $x$, we can add $\frac{1}{2}x$ to both sides of the equation:$$\frac{1}{2}x + \frac{1}{2}x = -\frac{1}{2}x + \frac{1}{2}x$$This simplifies to:$$x = 0$$

3. Verifying the Solution
To verify the solution, we substitute $x=0$ back into the equation $\frac{1}{2}x = -\frac{1}{2}x$:$$\frac{1}{2}(0) = -\frac{1}{2}(0)$$ $$0 = 0$$Since the equation holds true, our solution is correct.

4. Final Answer
Therefore, the value of $x$ that satisfies the equation is 0.

### Examples
Understanding how to solve simple algebraic equations like this is crucial in many real-world scenarios. For instance, imagine you're balancing a budget where expenses need to equal income. If you find that half of your income is exactly offset by a debt, this problem demonstrates how to determine that your income and debt are both zero, indicating a balanced budget with no surplus or deficit. This kind of problem-solving is also applicable in physics, engineering, and computer science.