Answer :
Final answer:
To calculate the mass of MgO that can be produced when 35.8 grams of Mg is available to react, use the balanced chemical equation and convert the given mass of Mg to moles. Then, convert the moles of MgO to mass. The mass of MgO that can be produced is 59.29 grams.
Explanation:
To calculate the mass of MgO that can be produced when 35.8 grams of Mg is available to react, we need to use the balanced chemical equation for the reaction:
2Mg + O2 → 2MgO
In this equation, the molar ratio between Mg and MgO is 2:2 (or 1:1). Therefore, for every 1 mole of Mg reacted, 1 mole of MgO is produced.
First, we need to convert the given mass of Mg to moles:
35.8 g Mg ÷ 24.305 g/mol Mg = 1.47 mol Mg
Since the molar ratio between Mg and MgO is 1:1, we can conclude that 1.47 moles of Mg will produce 1.47 moles of MgO.
Finally, we can convert the moles of MgO to mass:
1.47 mol MgO × 40.31 g/mol MgO = 59.29 grams of MgO
Learn more about Calculating mass of a product here:
https://brainly.com/question/26682140
#SPJ11
