Answer :
Final answer:
To identify the mass of solvent in the 4.22M aqueous H₂SO4 solution, we can calculate the mass of solute and subtract it from the total mass of the solution.
Explanation:
To identify the mass of solvent in the 4.22M aqueous H₂SO4 solution, we need to calculate the mass of solute and subtract it from the total mass of the solution. The density of the solution is given as 1.21 g/cm³. To calculate the mass of solute, we use the formula:
Mass of solute = Molarity × Molar mass × Volume of solution
In this case, the molarity of the solution is 4.22M, and the molar mass of H₂SO4 is 98.09 g/mol. The volume of the solution can be calculated using the density.
Using the given data, we can calculate the mass of solute as:
Mass of solute = 4.22M × 98.09 g/mol × Volume of solution
Once we have the mass of solute, we can find the mass of solvent by subtracting the mass of solute from the total mass of the solution. The mass of solvent in the 4.22M aqueous H₂SO4 solution is approximately 413.98 g.
