Answer :
The final probability is then 9/25.
The question involves calculating the probability of Jacqueline selecting two black checkers from a bag with replacement. To find this probability, we need to consider the event of selecting a black checker twice independently since the first checker is replaced before the second is drawn.
The probability of Jacqueline selecting a black checker on the first draw is 6 out of 10, or 6/10, since there are six black checkers and four red checkers. Since she replaces the checker, the probabilities remain the same for the second draw. Therefore, the probability of selecting a black checker on the second draw is also 6/10
The overall probability of selecting two black checkers is found by multiplying the individual probabilities together:
P(Black first draw) imes P(Black second draw) = 6/10 x 6/10 = 36/100 = [tex]\frac{9}{25}[/tex]
Hence, the probability that Jacqueline selects two black checkers with replacement is 9/25.
