High School

A waterbed filled with water has the dimensions [tex]8.0 \, \text{ft} \times 7.0 \, \text{ft} \times 0.75 \, \text{ft}[/tex]. Taking the density of water to be [tex]1.00 \, \text{g/cm}^3[/tex], how many kilograms of water are required to fill the waterbed?

A. 186 kg
B. 315 kg
C. 429 kg
D. 672 kg

Answer :

Final answer:

To fill the waterbed, approximately 1,045 kilograms of water are needed, which is closest to the provided option. A step-by-step calculation process using the dimensions and density of water was explained to determine the required mass accurately.

Explanation:

The mass of water required to fill the waterbed can be calculated by multiplying its dimensions. First, convert the dimensions to meters (1 ft = 0.3048 m) to get the volume in cubic meters. Then, multiply by the density of water to find the mass in kilograms.

Given dimensions: 8.0 ft x 7.0 ft x 0.75 ft.

Converting to meters: 2.4384 m x 2.1336 m x 0.2286 m.

Calculating the mass: (2.4384 m x 2.1336 m x 0.2286 m) x 1.00 g/cm³ = 1,044.6 kg.

Therefore, the correct answer is 1,045 kg, closest to option d. 672 kg.