Answer :
Final answer:
In Physics, the centripetal force keeping an object moving in a circular path is given by the formula Fc = mv^2/r. Applying this to the given scenario, the magnitude of the centripetal force on the go kart and the driver is approximately 473.81 N.
Explanation:
The subject of your question falls within the domain of Physics, specifically, it is about calculating the centripetal force acting on a moving object in a circular path.
Centripetal force is the force that keeps an object moving in a circular path. Its magnitude can be calculated using the formula: Fc = mv^2/r, where 'm' is the mass of the object, 'v' is the velocity of the object, and 'r' is the radius of the circular path.
Given the mass (m) as 143 kg, the velocity (v) as 13.8 m/s, and the radius (r) as 42.0 m. Substituting these values into the equation gives Fc = (143 kg) * (13.8 m/s)^2 / (42.0 m).
Therefore, the magnitude of the centripetal force on the go kart and the driver is approximately 473.81 N (Newtons).
Learn more about Centripetal Force here:
https://brainly.com/question/31417673
#SPJ3
Answer:
648.40N
Explanation:
Centripetal acceleration is the acceleration of an object around a circular path. Centripetal for e acting on the combined mass is expressed as:
F = ma
F = mv²/r
m is the mass of the object = 143kg
v is the linear velocity = 13.8m/s
r is the radius = 42.0m
Substitute the given parameters into the formula;
F = 143*13.8²/42
F = 27,232.92/42
F = 648.40N
Hence the magnitude of the centripetal force acting on the combined mass is 648.40N
