College

A crane lifts a load of 1000 N through a vertical height in 3 minutes and 10 seconds. The input power to the crane is 500 J/s. What is the efficiency of the crane?

Answer :

Based on the calculations, the efficiency of the crane is equal to 60%.

Given the following data:

  • Weight = 1000 Newton.
  • Height = 3.0 meters.
  • Time = 10 seconds.
  • Input power = 500J/s.

To calculate the efficiency of the crane:

How to calculate efficiency.

Mathematically, the efficiency of an object is given by this formula:

[tex]Efficiency = \frac{Out\;power}{In\;power} \times 100[/tex]

Next, we would determine the work done by the crane by using this formula:

[tex]Work\;done= weight \times height\\\\Work\;done=1000 \times 3.0[/tex]

Work done = 3000 J

For the output power:

[tex]Out\;power = \frac{work\;done}{time} \\\\Out\;power = \frac{3000}{10}[/tex]

Output power = 300 J/s.

Substituting the parameters into the formula, we have:

[tex]Efficiency = \frac{300}{500}\times 100\\\\Efficiency = 0.6 \times 100[/tex]

Efficiency = 60%.

Read more on efficiency here: https://brainly.com/question/996067

Answer:

0.6

Explanation:

We already have Weight and time and the input energy First we would find work done than divide by 10 (time) then we would have output energy after this apply efficiency formula output over input and then you would have the answer 0.6