Answer :
Final answer:
To find the pOH of a solution at 100°C with a pH of 6.25, we calculate the pKw from the given Kw and use the relationship pH + pOH = pKw. The pOH is found to be 7.75.
Explanation:
The student asked what the pOH of a solution is if it has a pH of 6.25 at 100°C and given that the Kw of water at this temperature is 5.6 x 10⁻¹³. To find the pOH, we first need to calculate the pKw, which is the negative base-10 logarithm of Kw. Using the given Kw value, pKw = -log(5.6 x 10⁻¹³). Once we have the pKw, we can use the relationship pH + pOH = pKw to find the pOH. Given the pH of 6.25, we can rearrange to pOH = pKw - pH. After computing the values, we find that the pOH of the solution at 100°C is 7.75.
