Answer :
The maximum speed v that the car can go without flying off the track is 22.2 m/s .
When the speed v of the car is sufficiently high, the normal force exerted by the road is insufficient to offer the centripetal force needed to keep the car on the track. At this speed, the car will leave the track and fly off into the air. The equation for centripetal force is:
F = mv2/r where F is the force, m is the mass, v is the velocity, and r is the radius of the circle.
If F is equal to the force of gravity, the vehicle can continue to travel in a circle.The force of gravity is calculated as follows:
F = mg where F is the force of gravity, m is the mass, and g is the acceleration due to gravity.
The force of gravity on this car is calculated as follows:
Fg = (648 kg)(9.8 m/s^2) = 6350.4 NTo get the maximum velocity, we must equate the force of gravity to the centripetal force, which isF = Fg = mv2/rWe can simplify this equation to get;
v² = Fr/mThe maximum velocity v can be calculated by solving this equation for v:v = √(Fr/m)Substitute the radius of the track and the coefficient of static friction into the equation to get:v = √(0.218 × 9.8 m/s² × 151 m / 648 kg) = 22.2 m/s.
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