Answer :
The ball goes to a height of 24.5 meters when thrown straight up into the air at 49 m/s.
The answer is not among the given options (a) 122.5m, (b) 110.5m, (c) 111.5m, and (d) 100.5m.
When a ball is thrown straight up into the air at 49m/s, the height it goes can be calculated using the following formula:
`v² = u² + 2as` where,
v = final velocity (0 m/s as the ball reaches maximum height)
u = initial velocity (49 m/s in this case)
a = acceleration due to gravity (-9.8 m/s²)
s = distance traveled (height the ball reaches)
Substituting the values in the above formula:
`0² = (49 m/s)² + 2(-9.8 m/s²)s`
Solving for s, we get:
`98s = (49 m/s)²`
`s = (49 m/s)²/98`
`s = 24.5 m`
Therefore, the ball goes to a height of 24.5 meters when thrown straight up into the air at 49 m/s. The answer is not among the given options (a) 122.5m, (b) 110.5m, (c) 111.5m, and (d) 100.5m.
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