Answer :
Final answer:
To find three consecutive odd integers summing to 441, the equation n + (n+2) + (n+4) = 441 is solved to find n = 145. Hence, the integers are 145, 147, 149. So, the correct option is B.
Explanation:
The problem asks us to find three consecutive odd integers with a sum of 441. If we let n be the smallest of these integers, the others can be represented as n+2 and n+4. To determine these integers, we set up the equation: n + (n+2) + (n+4) = 441. Simplifying this, we get 3n + 6 = 441. Subtracting 6 from both sides gives us 3n = 435, and dividing by 3 gives us n = 145. Therefore, the three consecutive odd integers are 145, 147, and 149.
In summary, sum all three integers expressed in terms of n, solve for n, then plug it back to find each integer. The correct answer is B. 145, 147, 149. This mathematical exercise demonstrates solving equations to find unknown values within a set of parameters.
