Answer :
Final answer:
The minimum force of friction required to prevent the motorcycle from sliding off the road is 499.36 N.
Explanation:
The minimum force of friction required to prevent the motorcycle from sliding off the road can be calculated using centripetal force. The centripetal force is given by the equation Fc = mv^2 / r, where Fc is the centripetal force, m is the mass of the motorcycle, v is the velocity, and r is the radius of the turn. Plugging in the given values, we have Fc = (126 kg)(19.7 m/s)^2 / 79.1 m = 499.36 N.
Learn more about Centripetal force here:
https://brainly.com/question/31417673
#SPJ11