Answer :
The vertices of the polygon form a trapezoid, and the area of the polygon is 28 unit squares.
The vertices are given as:
C = (3,3)
A = (8,-2)
S = (3,-4)
H = (0, -2)
The area of the polygon is calculated using:
[tex]A = \frac 12 \sum\limits^(n-1)_(k = 0)(x_ky_(k+1) - y_kx_(k+1))[/tex]
So, we have:
A = 1/2 * |(3 * -2 - 8 * 3 + 8 * -4 - 3 * -2 + 3 * -2 - 0 * -4 + 0 * 3 -3 * -2)|
Evaluate
A = 1/2 * |-56|
Remove the absolute bracket
A = 1/2 * 56
Evaluate the product
A= 28
Hence, the area of the polygon is 28 unit square
The vertices of the polygon form a trapezoid, and the area of the polygon is 28 unit squares
How to determine the area of the polygon?
The vertices are given as:
C = (3,3)
A = (8,-2)
S = (3,-4)
H = (0, -2)
The area of the polygon is calculated using:
[tex]A = \frac 12 \sum\limits^{n-1}_{k = 0}(x_ky_{k+1} - y_kx_{k+1})[/tex]
So, we have:
A = 1/2 * |(3 * -2 - 8 * 3 + 8 * -4 - 3 * -2 + 3 * -2 - 0 * -4 + 0 * 3 -3 * -2)|
Evaluate
A = 1/2 * |-56|
Remove the absolute bracket
A = 1/2 * 56
Evaluate the product
A= 28
Hence, the area of the polygon is 28 unit square
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