High School

0.8 litre of water flows in 5 minutes in a capillary tube of length 10 cm and of diameter of 1.5 mm. The height of the water surface is 45 cm from the axis of the capillary tube. Find the coefficient of viscosity of water.

Answer :

Final answer:

To find the coefficient of viscosity of water in a capillary tube, we can use Poiseuille's law for laminar flow.

Explanation:

To find the coefficient of viscosity of water, we can use Poiseuille's law for laminar flow. According to Poiseuille's law, the flow rate (Q) is directly proportional to the pressure difference (P2 - P1), and inversely proportional to the length of the tube (L) and the viscosity of the fluid (η). The flow rate can also be expressed as Q = A v, where A is the cross-sectional area of the tube and v is the average velocity of the water.

We know that 0.8 liters of water flows in 5 minutes, which is equivalent to 0.8/5 = 0.16 liters per minute. To convert this to SI units, we can use 1 liter = 0.001 cubic meters. Therefore, the flow rate Q = (0.16/60) cubic meters per second.

The cross-sectional area A of the tube can be calculated using the formula A = π r^2. Given the diameter of 1.5 mm, the radius r can be calculated as 0.75 mm = 0.00075 m. Substituting the values into the equation, we can solve for the viscosity η.

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