Answer :
The poll's margin of error is 0.0414, the confidence interval is 0, and the best point forecast for the population proportion is p = 0.6157. (0.5743, 0.6571)
What is a poll?
In order to represent the opinions of a population, opinion polls typically involve a series of questions and an attempt to extrapolate broad generalizations in ratio or within confidence intervals. A person who conducts polls is known as a pollster.
We have been given;
n = 916 people participated in the poll.
x = 564 is the number of people who said yes.
The formula would yield the population proportion;
p = x/n
p = 564/916
p = 0.6157
The formula for the margin of error is;
E = (z_α/2)√(p^(1 - p^)/n)
Where;
(z_α/2) is the critical value at the given confidence level.
The critical value z_α/2 for a confidence level of 99% from tables is: 2.576.
So,
E = 2.576√(0.6157(1 - 0.6157)/916)
E = 0.0414
The formula for the confidence interval is;
CI = p^ ± (z_α/2)√(p^(1 - p^)/n)
From B it can be known that
(z_α/2)√(p^(1 - p^)/n) = 0.0414
So,
CI = 0.6157 ± 0.0414
CI = (0.6157 - 0.0414), (0.6157 + 0.0414)
CI = (0.5743, 0.6571)
Thus, the answer for parts a, b, and c is p = 0.6157, E = 0.0414, and CI = (0.5743, 0.6571) respectively.
For more details regarding the poll, visit:
brainly.com/question/25737060
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Your question seems incomplete, the missing part of the question is:
(a) Find the best point estimate of the population proportion p.
(b) Identify the value of the margin of error E.
(c) Construct the confidence interval.
