High School

Which of the following equations have exactly one solution? Choose all answers that apply:

A. [tex]-6x - 6 = -6x - 103[/tex]

B. [tex]-103x - 6 = -6x - 103[/tex]

C. [tex]-6x - 6 = 103x - 103[/tex]

D. [tex]103x - 6 = 103x - 103[/tex]

Answer :

To determine which equations have exactly one solution, let's analyze each equation individually.

### Equation A: [tex]\(-6x - 6 = -6x - 103\)[/tex]

1. Start by simplifying both sides of the equation:
- The left side is [tex]\(-6x - 6\)[/tex].
- The right side is [tex]\(-6x - 103\)[/tex].

2. If we try to eliminate the [tex]\(-6x\)[/tex] terms from both sides, we get:
[tex]\(-6 = -103\)[/tex].

3. This statement is false, indicating there are no solutions for this equation.

### Equation B: [tex]\(-103x - 6 = -6x - 103\)[/tex]

1. Simplify and balance the equation:
- Move the terms involving [tex]\(x\)[/tex] to one side:
[tex]\(-103x + 6x = -103 + 6\)[/tex].

2. Simplify further:
[tex]\(-97x = -97\)[/tex].

3. Divide both sides by [tex]\(-97\)[/tex]:
[tex]\(x = 1\)[/tex].

Thus, Equation B has exactly one solution.

### Equation C: [tex]\(-6x - 6 = 103x - 103\)[/tex]

1. Simplify the equation by isolating terms involving [tex]\(x\)[/tex]:
- Rearrange terms:
[tex]\(-6x - 103x = -103 + 6\)[/tex].

2. Combine terms:
[tex]\(-109x = -97\)[/tex].

3. Divide both sides by [tex]\(-109\)[/tex]:
[tex]\(x = \frac{97}{109}\)[/tex].

Equation C has exactly one solution.

### Equation D: [tex]\(103x - 6 = 103x - 103\)[/tex]

1. Begin simplifying by eliminating the [tex]\(103x\)[/tex] terms from each side:
[tex]\(-6 = -103\)[/tex].

2. This statement is false, indicating there are no solutions for this equation.

In conclusion, the equations that have exactly one solution are Equation B and Equation C.