Answer :
To solve the problem of identifying which equation results in a different value of [tex]\( x \)[/tex] compared to the others, we'll look at each equation individually and solve for [tex]\( x \)[/tex].
1. Equation 1:
[tex]\[ 8.3 = -0.6x + 11.3 \][/tex]
- First, subtract 11.3 from both sides to get:
[tex]\[ 8.3 - 11.3 = -0.6x \][/tex]
[tex]\[ -3 = -0.6x \][/tex]
- Next, divide both sides by -0.6:
[tex]\[ x = \frac{-3}{-0.6} \][/tex]
[tex]\[ x = 5 \][/tex]
2. Equation 2:
[tex]\[ 11.3 = 8.3 + 0.6x \][/tex]
- Subtract 8.3 from both sides:
[tex]\[ 11.3 - 8.3 = 0.6x \][/tex]
[tex]\[ 3 = 0.6x \][/tex]
- Divide both sides by 0.6:
[tex]\[ x = \frac{3}{0.6} \][/tex]
[tex]\[ x = 5 \][/tex]
3. Equation 3:
[tex]\[ 11.3 - 0.6x = 8.3 \][/tex]
- Subtract 11.3 from both sides:
[tex]\[ -0.6x = 8.3 - 11.3 \][/tex]
[tex]\[ -0.6x = -3 \][/tex]
- Divide both sides by -0.6:
[tex]\[ x = \frac{-3}{-0.6} \][/tex]
[tex]\[ x = 5 \][/tex]
4. Equation 4:
[tex]\[ 8.3 - 0.6x = 11.3 \][/tex]
- Subtract 8.3 from both sides:
[tex]\[ -0.6x = 11.3 - 8.3 \][/tex]
[tex]\[ -0.6x = 3 \][/tex]
- Divide both sides by -0.6:
[tex]\[ x = \frac{3}{-0.6} \][/tex]
[tex]\[ x = -5 \][/tex]
By looking at the solutions for each equation, we see:
- Equations 1, 2, and 3 all have a solution of [tex]\( x = 5 \)[/tex].
- Equation 4 has a solution of [tex]\( x = -5 \)[/tex].
Therefore, the equation that results in a different value of [tex]\( x \)[/tex] is the fourth equation: [tex]\( 8.3 - 0.6x = 11.3 \)[/tex].
1. Equation 1:
[tex]\[ 8.3 = -0.6x + 11.3 \][/tex]
- First, subtract 11.3 from both sides to get:
[tex]\[ 8.3 - 11.3 = -0.6x \][/tex]
[tex]\[ -3 = -0.6x \][/tex]
- Next, divide both sides by -0.6:
[tex]\[ x = \frac{-3}{-0.6} \][/tex]
[tex]\[ x = 5 \][/tex]
2. Equation 2:
[tex]\[ 11.3 = 8.3 + 0.6x \][/tex]
- Subtract 8.3 from both sides:
[tex]\[ 11.3 - 8.3 = 0.6x \][/tex]
[tex]\[ 3 = 0.6x \][/tex]
- Divide both sides by 0.6:
[tex]\[ x = \frac{3}{0.6} \][/tex]
[tex]\[ x = 5 \][/tex]
3. Equation 3:
[tex]\[ 11.3 - 0.6x = 8.3 \][/tex]
- Subtract 11.3 from both sides:
[tex]\[ -0.6x = 8.3 - 11.3 \][/tex]
[tex]\[ -0.6x = -3 \][/tex]
- Divide both sides by -0.6:
[tex]\[ x = \frac{-3}{-0.6} \][/tex]
[tex]\[ x = 5 \][/tex]
4. Equation 4:
[tex]\[ 8.3 - 0.6x = 11.3 \][/tex]
- Subtract 8.3 from both sides:
[tex]\[ -0.6x = 11.3 - 8.3 \][/tex]
[tex]\[ -0.6x = 3 \][/tex]
- Divide both sides by -0.6:
[tex]\[ x = \frac{3}{-0.6} \][/tex]
[tex]\[ x = -5 \][/tex]
By looking at the solutions for each equation, we see:
- Equations 1, 2, and 3 all have a solution of [tex]\( x = 5 \)[/tex].
- Equation 4 has a solution of [tex]\( x = -5 \)[/tex].
Therefore, the equation that results in a different value of [tex]\( x \)[/tex] is the fourth equation: [tex]\( 8.3 - 0.6x = 11.3 \)[/tex].
