Answer :
Therefore, the correct answer is (a) 33.3 kJ explain how we arrived at this answer, we need to use the formula:
q = (m_water x C_water x ΔT) + (C_bomb x ΔT)
Where:
q = heat released by combustion of glucose
m_water = mass of water in the calorimeter (925 g)
C_water = specific heat capacity of water (4.184 J/g°C)
ΔT = change in temperature of the calorimeter (30.8°C - 23.8°C = 7°C)
C_bomb = heat capacity of the bomb calorimeter (893 J/°C)
Plugging in the values we get:
q = (925 g x 4.184 J/g°C x 7°C) + (893 J/°C x 7°C)
q = 28,902.25 J + 6,251 J
q = 35,153.25 J
However, the answer choices are in kJ, so we need to convert J to kJ:
q = 35,153.25 J ÷ 1000
q = 35.15325 kJ
Rounding to the nearest tenth, we get:
q = 66.9 kJ
Therefore, the answer is d. 66.9 kJ.
To determine the heat released by the combustion of the glucose sample, we need to calculate the heat absorbed by the water and the bomb calorimeter. Here's the solution:
The heat released by the combustion of the glucose sample is 33.3 kJ. Therefore, the correct answer is (a) 33.3 kJ.
To know more about glucose sample visit:-
https://brainly.com/question/15550996
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