Answer :
To find the potential energy of a bicycle resting at the top of a hill, we can use the formula for gravitational potential energy:
[tex]\[ PE = m \times g \times h \][/tex]
Where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex] on Earth),
- [tex]\( h \)[/tex] is the height above the ground (in meters).
Let's plug in the values given in the problem:
- The mass ([tex]\( m \)[/tex]) of the bicycle is 25 kg,
- The height ([tex]\( h \)[/tex]) of the hill is 3 m,
- The acceleration due to gravity ([tex]\( g \)[/tex]) is 9.8 m/s².
Now, calculate the potential energy:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is 735 Joules. This matches the correct answer choice, which is 735 J.
[tex]\[ PE = m \times g \times h \][/tex]
Where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex] on Earth),
- [tex]\( h \)[/tex] is the height above the ground (in meters).
Let's plug in the values given in the problem:
- The mass ([tex]\( m \)[/tex]) of the bicycle is 25 kg,
- The height ([tex]\( h \)[/tex]) of the hill is 3 m,
- The acceleration due to gravity ([tex]\( g \)[/tex]) is 9.8 m/s².
Now, calculate the potential energy:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is 735 Joules. This matches the correct answer choice, which is 735 J.
