Answer :
To find the potential energy of a 25 kg bicycle at the top of a hill 3 meters high, you use the formula for potential energy:
[tex]\[ PE = m \times g \times h \][/tex]
where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the object,
- [tex]\( g \)[/tex] is the acceleration due to gravity,
- [tex]\( h \)[/tex] is the height above the ground.
In the problem:
- The mass [tex]\( m \)[/tex] is 25 kg,
- The acceleration due to gravity [tex]\( g \)[/tex] is approximately 9.8 m/s²,
- The height [tex]\( h \)[/tex] is 3 m.
Now, plug in the given values:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
When you multiply these numbers together:
[tex]\[ PE = 25 \times 9.8 \times 3 \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the bicycle is 735 Joules, which matches the second option [tex]\( \text{735 J} \)[/tex].
[tex]\[ PE = m \times g \times h \][/tex]
where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the object,
- [tex]\( g \)[/tex] is the acceleration due to gravity,
- [tex]\( h \)[/tex] is the height above the ground.
In the problem:
- The mass [tex]\( m \)[/tex] is 25 kg,
- The acceleration due to gravity [tex]\( g \)[/tex] is approximately 9.8 m/s²,
- The height [tex]\( h \)[/tex] is 3 m.
Now, plug in the given values:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
When you multiply these numbers together:
[tex]\[ PE = 25 \times 9.8 \times 3 \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the bicycle is 735 Joules, which matches the second option [tex]\( \text{735 J} \)[/tex].
