High School

Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ What is the pH of a 0.250 M solution that is 2.31% ionized?

A. 0.238
B. 1.64
C. 2.24
D. 0.602

Answer :

Final answer:

The pH of the 0.250 M solution that is 2.31% ionized is 2.24.

Explanation:

To calculate the pH of a solution, we need to determine the concentration of hydrogen ions (H+). In this case, we have a 0.250 M solution that is 2.31% ionized. This means that 2.31% of the solute has dissociated into ions.

To find the concentration of H+ ions, we can multiply the initial concentration of the solution (0.250 M) by the ionization percentage (2.31% or 0.0231).

Concentration of H+ ions = 0.250 M x 0.0231 = 0.005775 M

Now that we have the concentration of H+ ions, we can calculate the pH using the formula:

pH = -log[H+]

Substituting the concentration of H+ ions into the formula:

pH = -log(0.005775) = 2.24

Learn more about calculating the ph of a solution here:

https://brainly.com/question/28227384

#SPJ14

Other Questions