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------------------------------------------------ What is the molarity of an aqueous solution containing 75.3 g of glucose ([tex]C_6H_{12}O_6[/tex]) dissolved in 35.5 mL of solution?

To find the molarity of an aqueous solution, calculate the moles of glucose and use the formula Molarity (M) = moles of solute / volume of solution (in liters).

Explanation:

To find the molarity of an aqueous solution, we need to first calculate the number of moles of glucose present in the solution. The molarity (M) is defined as moles of solute per liter of solution. We can use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's calculate the moles of glucose:

Moles of glucose = mass of glucose / molar mass of glucose

The molar mass of glucose (C6H12O6) is calculated by adding the molar masses of carbon (C), hydrogen (H), and oxygen (O).

Molar mass of C6H12O6 = (6 * atomic mass of C) + (12 * atomic mass of H) + (6 * atomic mass of O)

Once we have the moles of glucose and volume of solution in liters, we can calculate the molarity. Remember to convert the volume from milliliters to liters:

Molarity = moles of glucose / volume of solution (in liters)

Substituting the values we have:

Molarity = (moles of glucose) / (volume of solution in liters)

Be sure to use correct units and round the final answer to an appropriate number of significant figures.

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