The 50 cars used by a firm were inspected for faults.

- 35 cars had faulty brakes.
- 15 cars had faulty tires.
- 2 cars had faulty brakes but good tires.

How many cars had good brakes?

Let's assume that the number of cars with faulty brakes is x. Since there are 2 cars with faulty brakes and good tyres, the total number of cars with faulty brakes would be x + 2.The number of cars with faulty tyres is 15.

We can write an equation that includes all the information given in the question:

x + 2 + 15 = 50

This is because the total number of cars (50) equals the sum of the number of cars with faulty brakes (x + 2) and the number of cars with faulty tyres (15).

Now we can solve for x:x + 2 + 15 = 50x + 17 = 50x = 33.

Therefore, there were 33 cars with faulty brakes. To determine how many cars had good brakes, we subtract the number of cars with faulty brakes from the total number of cars:50 - 33 = 17. Therefore, 17 cars had good brakes.

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The 50 cars used by a firm were inspected for faults. - 35 cars had faulty brakes.- 15 cars had faulty tires.- 2 cars had faulty brakes but good tires.How many cars had good brakes?

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The 50 cars used by a firm were inspected for faults.

- 35 cars had faulty brakes.
- 15 cars had faulty tires.
- 2 cars had faulty brakes but good tires.

How many cars had good brakes?