Answer :
Final answer:
The concentration of nitrate ions in a 6.00 M Sr(NO3)2 solution is 12.00 M, because each formula unit of Sr(NO3)2 produces two nitrate ions when it dissolves in the solution.
Explanation:
The concentration of nitrate ions in a 6.00 M Sr(NO3)2 solution involves determining the molarity of the nitrate ions. Each formula unit of Sr(NO3)2 produces one Sr2+ ion and two NO3- ions when it dissolves. Therefore, the molarity of the nitrate ions is two times the molarity of the Sr(NO3)2. Thus, the concentration of nitrate ions in the solution is 2 * 6.00 M = 12.00 M. This means that there are 12.00 moles of nitrate ions in every liter of the solution. Always remember, the molarity of the ions in the solution is multiplied by the number of those ions produced by each formula unit of the compound.
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