High School

Wanda has a home-based business making corsages and boutonnieres. Last year, she sold 24 corsages and 36 boutonnieres, which brought in a total of $1,176. This year, she sold 33 corsages and 22 boutonnieres, for a total of $1,012. How much does each item sell for?

Answer :

Final answer:

By setting up a system of linear equations from the sales data provided and solving it, the cost of corsages is found to be $14 each, and boutonnieres are $22 each.

Explanation:

To solve the problem of determining the individual prices of the corsages and boutonnieres Wanda sold, we will set up a system of linear equations based on the information provided. In the first year, Wanda sold 24 corsages (C) and 36 boutonnieres (B), bringing in a total of $1,176. In the second year, she sold 33 corsages and 22 boutonnieres for a total of $1,012.

From the first year's sales, we have the equation 24C + 36B = 1176. From the second year's sales, the equation is 33C + 22B = 1012. These can be simplified (by dividing the first by 12 and the second by 11) to 2C + 3B = 98 and 3C + 2B = 92, respectively. We now have a simpler system of equations:

  • 2C + 3B = 98
  • 3C + 2B = 92

Solving this system will give us the individual prices of the corsages (C) and boutonnieres (B). To solve it, we can use either substitution or elimination method. Let's use elimination:

  1. Multiply the first equation by 3 and the second by 2: 6C + 9B = 294 and 6C + 4B = 184.
  2. Subtract the second equation from the first: 5B = 110.
  3. Solve for B: B = 22.
  4. Substitute B = 22 into the initial simplified equation: 2C + 3(22) = 98.
  5. Solve for C: C = 14.

Therefore, the corsages sell for $14 each and the boutonnieres sell for $22 each.