Answer :
38.8 g of neon occupies a volume of 42.85 L at STP.
The molar volume of a gas at STP (standard temperature and pressure) is defined as the volume occupied by one mole of the gas at a temperature of 0 °C (273.15 K) and a pressure of 1 atm (101.325 kPa).
The molar volume of an ideal gas at STP is approximately 22.4 L/mol.
To determine the volume occupied by 38.8 g of neon at STP, we need to first convert the mass of neon to moles. The molar mass of neon is 20.18 g/mol. Therefore:
moles of neon = mass of neon / molar mass of neon
= 38.8 g / 20.18 g/mol
= 1.92 mol
Next, we can use the molar volume of an ideal gas at STP to calculate the volume occupied by 1.92 moles of neon:
volume of neon at STP = moles of neon x molar volume of neon at STP
= 1.92 mol x 22.4 L/mol
= 42.85 L
Therefore, 38.8 g of neon occupies a volume of 42.85 L at STP.
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