Answer :
Using the formula for energy as the product of charge and voltage (E = Q * V), 6 coulombs flowing through a filament powered by a 6-volt battery yields 36 Joules of energy. Dividing this energy by the time, 2 seconds, we find the power to be d) 18 watts.
The student is dealing with a Physics question related to electric charge and energy. Specifically, we are examining the scenario with 6 coulombs of charge flowing through a bulb filament powered by a 6 volt battery for 2 seconds. To find the answer, we can use the relationship between charge (Q), voltage (V), and energy (E), which is given by the formula E = Q * V. Here, Q is 6 coulombs, and V is 6 volts, so the energy
E = 6 C * 6 V = 36 Joules.
However, since the charge flows over a period of 2 seconds, to find the power, we divide the energy by the time. The power P is thus 36 Joules / 2 seconds = 18 Watts. Therefore, the correct answer is d) 18 watts.
