Answer :
According to the ideal gas law, 4.30 molecule of o2 occupies 0.11 m³ at 99.7 kPa with 35.0 °C.
What is a straightforward definition of ideal gas law?
The relationship between a gas's pressure P, volumes V, and t in the range between low pressures and extremely high temperatures, when the gas's water moves virtually independently of one another, is known as the ideal gas, also known as the perfect gas law.
PV = nRTp = pressure in PaV
= volume in m³n = number of molesR
= molar gas constant (8.31 JK⁻¹mol⁻¹)T
= temperature in Kpressure ⇒ 99.7 × 10³ Pa
temperature ⇒ 35.0 + 273 = 308
KpV = nRT
= 99.7×10³×V= 4.30×8.31×308V
=(4.30×8.31×308)/(99.7×10³3 )V
= 0.11 m³
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