College

Type the correct answer in each box. If necessary, round your answers to the nearest tenth. Use the conversion formulas for Celsius and Fahrenheit to find the missing values in the table.

\[
\begin{tabular}{|c|c|}
\hline
\multicolumn{2}{|c|}{Temperature} \\
\hline
Degrees Celsius & Degrees Fahrenheit \\
\hline
10 & $\square$ \\
\hline
$\square$ & 87 \\
\hline
-5 & $\square$ \\
\hline
$\square$ & 10 \\
\hline
\end{tabular}
\]

Conversion Formulas:

1. Fahrenheit to Celsius: [tex]C = \frac{5}{9}(F - 32)[/tex]

2. Celsius to Fahrenheit: [tex]F = \frac{9}{5}C + 32[/tex]

Answer :

We begin by recalling the conversion formulas between Celsius and Fahrenheit:

[tex]$$
\text{Celsius to Fahrenheit:} \quad F = \frac{9}{5}C + 32
$$[/tex]

[tex]$$
\text{Fahrenheit to Celsius:} \quad C = \frac{5}{9}(F - 32)
$$[/tex]

Now, we will solve each row in the table step-by-step.

–––––––––––––––
Step 1. Convert 10°C to Fahrenheit:

Given the temperature is [tex]$10^\circ C$[/tex], we use the Celsius-to-Fahrenheit formula:

[tex]$$
F = \frac{9}{5}(10) + 32 = 18 + 32 = 50.0
$$[/tex]

Thus, [tex]$10^\circ C$[/tex] is equivalent to [tex]$50.0^\circ F$[/tex].

–––––––––––––––
Step 2. Convert 87°F to Celsius:

We are given [tex]$87^\circ F$[/tex], and we convert to Celsius using the Fahrenheit-to-Celsius formula:

[tex]$$
C = \frac{5}{9}(87 - 32)
$$[/tex]

First, subtract 32 from 87:

[tex]$$
87 - 32 = 55
$$[/tex]

Now, multiply by [tex]$\frac{5}{9}$[/tex]:

[tex]$$
C = \frac{5}{9}(55) \approx 30.6
$$[/tex]

Thus, [tex]$87^\circ F$[/tex] is approximately [tex]$30.6^\circ C$[/tex] (rounded to the nearest tenth).

–––––––––––––––
Step 3. Convert -5°C to Fahrenheit:

Using the Celsius-to-Fahrenheit formula for [tex]$-5^\circ C$[/tex]:

[tex]$$
F = \frac{9}{5}(-5) + 32 = -9 + 32 = 23.0
$$[/tex]

Thus, [tex]$-5^\circ C$[/tex] is equivalent to [tex]$23.0^\circ F$[/tex].

–––––––––––––––
Step 4. Convert 10°F to Celsius:

Given [tex]$10^\circ F$[/tex], we apply the Fahrenheit-to-Celsius formula:

[tex]$$
C = \frac{5}{9}(10 - 32)
$$[/tex]

Subtract 32 from 10:

[tex]$$
10 - 32 = -22
$$[/tex]

Now, multiply by [tex]$\frac{5}{9}$[/tex]:

[tex]$$
C = \frac{5}{9}(-22) \approx -12.2
$$[/tex]

Thus, [tex]$10^\circ F$[/tex] is approximately [tex]$-12.2^\circ C$[/tex].

–––––––––––––––
Summary of the completed table:

[tex]$$
\begin{array}{|c|c|}
\hline
\textbf{Degrees Celsius} & \textbf{Degrees Fahrenheit} \\
\hline
10 & 50.0 \\
\hline
30.6 & 87 \\
\hline
-5 & 23.0 \\
\hline
-12.2 & 10 \\
\hline
\end{array}
$$[/tex]

Each conversion has been rounded to the nearest tenth as required.