Answer :
Using Ohm's law (I = V/R), the current flowing through a light bulb with a resistance of 2 ohms connected to a 12 V battery is calculated to be 6 amps.
If a 12 V battery is connected to a light bulb with a resistance of 2 ohms, we can determine how much current will flow through the light bulb by using Ohm's law, which is represented by the equation I = V/R, where I is the current in amperes (A), V is the voltage in volts (V), and R is the resistance in ohms (Ω). Substituting the known values into the equation gives us I = 12 V / 2 Ω = 6 A. Therefore, the current flowing through the light bulb is 6 amps (Option C).
It's important to differentiate between current and other quantities such as power and resistance. While the question mentions a 12 V battery, which is a measure of electric potential, and a resistance of 2 ohms, neither power (measured in watts) nor resistance in ohms (Ω) is relevant in calculating the current.
Answer:
6amp
Explanation:
From Ohm's Law
V = IR
Where V = 12volts, R = 2ohms
12volts = I × 2ohms
I = 12/2
I = 6amp
The current flowing through the light bulb is 6amp
