Answer :
When two resistors, 7 ohms and 6 ohms, are connected in parallel with a 7 V battery, the current is found to be approximately 1.55 A.
To find the total resistance of the parallel combination of the two resistors, we use the formula:
1/R(total) = 1/R1 + 1/R2
Substituting the given values:
1/R(total) = 1/7 + 1/6
Simplifying the equation:
1/R(total) = (6 + 7)/(7 * 6)
1/R(total) = 13/42
R(total) = 42/13
Now, we can use Ohm's Law to calculate the current (I) through the battery:
I = V/R(total)
Substituting the given voltage (V = 7 V) and the calculated resistance (R(total) = 42/13):
I = 7 / (42/13)
I ≈ 1.55 A
Therefore, the current flowing through the battery is approximately 1.55 amperes (A).
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