Answer :
The lens in question is a converging lens and the image formed is virtual.
The correct answer to the given question is option A.
Based on the given information, we can determine the type of lens and whether the resulting image is real or virtual. Let's analyze the situation:
The object is located 1.55 m away from the lens, which we can consider as a positive distance. The image, on the other hand, is formed 48.8 cm (0.488 m) on the opposite side of the lens.
To determine the type of lens, we can use the lens formula:
1/f = 1/v - 1/u,
where f is the focal length of the lens, v is the image's distance from the lens, and u is the object's distance from the lens.
When the above values are substituted into the formula, the following results are obtained:
1/f = 1/0.488 - 1/1.55.
Simplifying the equation, we find:
1/f = 2.049 - 0.645.
1/f = 1.404.
From the equation, it is clear that the focal length is positive, indicating that the lens is converging (option A).
To determine whether the image formed is real or virtual, we can use the sign convention. In this case, the image is formed on the opposite side of the lens, which is considered negative. Therefore, the negative value indicates that the image is virtual.
In summary, based on the given information, the lens in question is a converging lens (option A), and the image formed is virtual.
For more such questions on converging lens, click on:
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